[pmwiki-users] Any way to get page counts with breaks based on a PTV?

[Petko Yotov]

I've added this for 2.2.121. There will be a new pseudovariable 
{$$EachCount} similar to {$$PageGroupCount} that will contain the number 
of pages in the current "each" loop.

I'm not sure if the name {$$EachCount} is good, could be 
{$$CurrentLoopCount} or something else, if anyone has ideas, before we 
release it.

To test this, please get the prerelease as a ZIP file from the ChangeLog 
page, or from Subversion (only scripts/pagelist.php is updated for 
this).

So in your template you can use {$$EachCount}:

(:template last "{=$:department}":)
{=$:department} contains {$$EachCount} pages.

See for example, Cookbook.B* pages, ordered by maintainer:

   https://www.pmwiki.org/wiki/Test/EachCount

If you use (:template last "{=$:department}":) you need to also order 
the pagelist by $:department, like you did.

Petko

On 11/11/2019 21:14, Christopher Cox wrote:
> Consider the following template and assume a SysUser group with pages
> of users having the PTVs: department, name and active.
> 
> [[#test1]]
> (:template defaults order=$:department:)
> (:template first {=$:department}:)
> 
> Users in {=$:department}
> (:template each:)
> (:if equal {=$:active} true:)
> * [[{=$FullName}|{=$:name}]]
> (:ifend:)
> (:template last {=$:department}:)
> {=$:department} contains ???? pages.
> [[#test1end]]
> 
> 
> My question is if there's any way to get establish a counter that is
> zeroed for each new department and can be referenced in the "last"
> where I have the ????.
> 
> I know there are counters for pages and groups.  Here, it's the same
> group, and I want a counter that I can set somehow based on the PTV
> change.  Possible?
> 
> Ultimately, I'm hoping to use such things to generate pie charts (in
> case you wondering).
> 
> Department  Count
> ----------  -----
> IT          3
> Accounting  5
> etc..
> 
> Yes, I know I can do this with lots of individual pagelists, just
> trying to see if there was a more efficient way.