<HTML><BODY style="word-wrap: break-word; -khtml-nbsp-mode: space; -khtml-line-break: after-white-space; "><BR><DIV><DIV>On Oct 27, 2006, at 6:52 AM, marc wrote:</DIV><BR class="Apple-interchange-newline"><BLOCKQUOTE type="cite"><P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">Without looking more closely, have you read this from the PHP manual:</FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px Comic Sans MS; min-height: 16.0px"><BR></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">Note: Also note that foreach operates on a copy of the specified array<SPAN class="Apple-converted-space"> </SPAN></FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">and not the array itself. Therefore, the array pointer is not modified<SPAN class="Apple-converted-space"> </SPAN></FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">as with the each() construct, and changes to the array element returned<SPAN class="Apple-converted-space"> </SPAN></FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">are not reflected in the original array. However, the internal pointer<SPAN class="Apple-converted-space"> </SPAN></FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">of the original array is advanced with the processing of the array.<SPAN class="Apple-converted-space"> </SPAN></FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">Assuming the foreach loop runs to completion, the array's internal<SPAN class="Apple-converted-space"> </SPAN></FONT></P> <P style="margin: 0.0px 0.0px 0.0px 0.0px"><FONT face="Comic Sans MS" size="3" style="font: 12.0px Comic Sans MS">pointer will be at the end of the array.<SPAN class="Apple-converted-space"> </SPAN></FONT></P> </BLOCKQUOTE></DIV><BR><DIV>I think you said what I said about this, but frankly unless one is actually a programmer, the PHP manual's text doesn't make much sense. Talking about pointers and copies of arrays, etc. is not going to be much help to someone that doesn't understand the implications of those terms. When y'all had the discussion of whether or not variables were copied or not some of it was over my head -- it's not like I have a computer science degree ;)</DIV><DIV><BR class="khtml-block-placeholder"></DIV><DIV>Crisses</DIV></BODY></HTML>