[pmwiki-users] Permission to see source...

[Patrick R. Michaud]

On Wed, Apr 11, 2007 at 01:02:09PM -0400, The Editor wrote:
> 
> Actually, I have a markup I only want to work if someone has
> permission to see the source of a page.  I need something like  if
> (condauth('source')) ... but there is no source level, so I need a
> different approach...

CondAuth($pagename, $HandleAuth['source'])

Pm